Swift 2.0 Format 1000's into a friendly K's

Question

I\'m trying to write a function to present thousands and millions into K\'s and M\'s For instance:

1000 = 1k
1100 = 1.1k
15000 = 15k
115000 = 115k
1000000 =          


        

Answer 1

Minor improvement to @chrisz answer, Swift-4 Doble extension - This works fine in all cases.

extension Double {

  // Formatting double value to k and M
  // 1000 = 1k
  // 1100 = 1.1k
  // 15000 = 15k
  // 115000 = 115k
  // 1000000 = 1m
  func formatPoints() -> String{
        let thousandNum = self/1000
        let millionNum = self/1000000
        if self >= 1000 && self < 1000000{
            if(floor(thousandNum) == thousandNum){
                return ("\(Int(thousandNum))k").replacingOccurrences(of: ".0", with: "")
            }
            return("\(thousandNum.roundTo(places: 1))k").replacingOccurrences(of: ".0", with: "")
        }
        if self > 1000000{
            if(floor(millionNum) == millionNum){
                return("\(Int(thousandNum))k").replacingOccurrences(of: ".0", with: "")
            }
            return ("\(millionNum.roundTo(places: 1))M").replacingOccurrences(of: ".0", with: "")
        }
        else{
            if(floor(self) == self){
                return ("\(Int(self))")
            }
            return ("\(self)")
        }
    }

    /// Returns rounded value for passed places
    ///
    /// - parameter places: Pass number of digit for rounded value off after decimal
    ///
    /// - returns: Returns rounded value with passed places
    func roundTo(places:Int) -> Double {
        let divisor = pow(10.0, Double(places))
        return (self * divisor).rounded() / divisor
    }
}