Swift 2.0 Format 1000's into a friendly K's

Question

I\'m trying to write a function to present thousands and millions into K\'s and M\'s For instance:

1000 = 1k
1100 = 1.1k
15000 = 15k
115000 = 115k
1000000 =          


        

Answer 1

Solution above (from @qlear) in Swift 3:

func formatPoints(num: Double) -> String {
    var thousandNum = num / 1_000
    var millionNum = num / 1_000_000
    if  num >= 1_000 && num < 1_000_000 {
        if  floor(thousandNum) == thousandNum {
            return("\(Int(thousandNum))k")
        }
        return("\(thousandNum.roundToPlaces(1))k")
    }
    if  num > 1_000_000 {
        if  floor(millionNum) == millionNum {
            return "\(Int(thousandNum))k"
        }
        return "\(millionNum.roundToPlaces(1))M"
    }
    else{
        if  floor(num) == num {
            return "\(Int(num))"
        }
        return "\(num)"
    }
}

extension Double {
    // Rounds the double to decimal places value
    mutating func roundToPlaces(_ places : Int) -> Double {
        let divisor = pow(10.0, Double(places))
        return (self.rounded() * divisor) / divisor
    }
}