Printing a char with printf

Question

Are both these codes the same

char ch = \'a\';
printf(\"%d\", ch);

Will it print a garbage value?

I am confused about this

Answer 1

This is supposed to print the ASCII value of the character, as %d is the escape sequence for an integer. So the value given as argument of printf is taken as integer when printed.

char ch = 'a';
printf("%d", ch);

Same holds for printf("%d", '\0');, where the NULL character is interpreted as the 0 integer.

Finally, sizeof('\n') is 4 because in C, this notation for characters stands for the corresponding ASCII integer. So '\n' is the same as 10 as an integer.

It all depends on the interpretation you give to the bytes.