Gulp returns 0 when tasks fail

Question

I\'m using Gulp in my small project in order to run tests and lint my code. When any of those tasks fail, Gulp always exits with return code 0. If I run jshint by hand, it e

Answer 1

@robrich is right, you have to keep track of exit codes yourself, but there's no need for a forceful approach. The process global is an EventEmitter which you can bind your exit function to.

var exitCode = 0

gulp.task('test', function (done) {
  return require('child_process')
    .spawn('npm', ['test'], {stdio: 'pipe'})
    .on('close', function (code, signal) {
      if (code) exitCode = code
      done()
    })
})

gulp.on('err', function (err) {
  process.emit('exit') // or throw err
})

process.on('exit', function () {
  process.nextTick(function () {
    process.exit(exitCode)
  })
})