Typescript Duplicate Function Implementation

Question

I have defined the following two function signatures in the same Typescript class, i.e.,

public emit(event: string, arg1: T1): void {}
         


        

Answer 1

I'm assuming your code looks like this:

public emit(event: string, arg1: T1): void {}
public emit(event: string, arg1: T1, arg2: T2): void {}
public emit(event: string, ...args: any[]): void {
    // actual implementation here
}

The problem is that you have {} after the first 2 lines. This actually defines an empty implementation of a function, i.e. something like:

function empty() {}

You only want to define a type for the function, not an implementation. So replace the empty blocks with just a semi-colon:

public emit(event: string, arg1: T1): void;
public emit(event: string, arg1: T1, arg2: T2): void;
public emit(event: string, ...args: any[]): void {
    // actual implementation here
}