Why does Java require an explicit cast on a final variable if it was copied from an array?

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长发绾君心
长发绾君心 2021-01-01 08:28

Starting with the following code...

byte foo = 1;
byte fooFoo = foo + foo;

When I try compiling this code I will get the following error...

4条回答
  •  迷失自我
    2021-01-01 08:54

    The JLS (§5.2) has special rules for assignment conversion with constant expressions:

    In addition, if the expression is a constant expression (§15.28) of type byte, short, char, or int:

    • A narrowing primitive conversion may be used if the type of the variable is byte, short, or char, and the value of the constant expression is representable in the type of the variable.

    If we follow the link above, we see these in the definition of constant expression:

    • Literals of primitive type and literals of type String
    • The additive operators + and -
    • Simple names (§6.5.6.1) that refer to constant variables (§4.12.4).

    If we follow the second link above, we see that

    A variable of primitive type or type String, that is final and initialized with a compile-time constant expression (§15.28), is called a constant variable.

    It follows that foo + foo can only be assigned to fooFoo if foo is a constant variable. To apply that to your cases:

    • byte foo = 1; does not define a constant variable because it's not final.

    • final byte foo = 1; does define a constant variable, because it's final and initialized with a constant expression (a primitive literal).

    • final byte foo = fooArray[0]; does not define a constant variable because it's not initialized with a constant expression.

    Note that whether fooFoo is itself final doesn't matter.

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