find the “string length” of an int

Question

basically I want to return the number of digits in the int -> values like this:

(int)1 => 1
(int)123 => 3
(int)12345678 => 8

I kno

Answer 1

use

int d = (value == 0 ? 1 : (int)(log10(value)+1));

Note that this doesnt work for negative numbers, you'll have to use

int d = (value == 0 ? 1 : ((int)(log10(fabs(value))+1) + (value < 0 ? 1 : 0)));

which adds 1 for the minus sign, if value is negative.