I\'m planning to use concurrent.futures.ProcessPoolExecutor
to parallelize execution of functions. According to the documentation, its executor
obj
It sounds like you're looking for an equivalent to the initializer
/initargs
options that multiprocessing.Pool takes. Currently, that behavior doesn't exist for concurrent.futures.ProcessPoolExecutor
, though there is a patch waiting for review that adds that behavior.
So, you can either use multiprocessing.Pool
(which might be fine for your usecase), wait for that patch to get merged and released (you might be waiting a while :)), or roll your own solution. Turns out, it's not too hard to write a wrapper function for map that takes an initializer
, but only calls it one per process:
from concurrent.futures import ProcessPoolExecutor
from functools import partial
inited = False
initresult = None
def initwrapper(initfunc, initargs, f, x):
# This will be called in the child. inited
# Will be False the first time its called, but then
# remain True every other time its called in a given
# worker process.
global inited, initresult
if not inited:
inited = True
initresult = initfunc(*initargs)
return f(x)
def do_init(a,b):
print('ran init {} {}'.format(a,b))
return os.getpid() # Just to demonstrate it will be unique per process
def f(x):
print("Hey there {}".format(x))
print('initresult is {}'.format(initresult))
return x+1
def initmap(executor, initializer, initargs, f, it):
return executor.map(partial(initwrapper, initializer, initargs, f), it)
if __name__ == "__main__":
with ProcessPoolExecutor(4) as executor:
out = initmap(executor, do_init, (5,6), f, range(10))
print(list(out))
Output:
ran init 5 6
Hey there 0
initresult is 4568
ran init 5 6
Hey there 1
initresult is 4569
ran init 5 6
Hey there 2
initresult is 4570
Hey there 3
initresult is 4569
Hey there 4
initresult is 4568
ran init 5 6
Hey there 5
initresult is 4571
Hey there 6
initresult is 4570
Hey there 7
initresult is 4569
Hey there 8
initresult is 4568
Hey there 9
initresult is 4570
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]