Compare nested objects in JavaScript and return keys equality

Question

I have two nested objects obj1 and obj2 and I want to compare them and the recursively return an object that for each nested key has a equality-lik

Answer 1

A recursive example,

var obj1 = {
        prop1: 1,
        prop2: "foo",
        prop3: {
            prop4: 2,
            prop5: "bar"
        },
        prop7: {},
    }

    var obj2 = {
        prop1: 3,
        prop2: "foo",
        prop3: {
            prop4: 2,
            prop5: "foobar"
        },
        prop6: "new",
        prop7: {},
        prop8: {},
    }

    var result = {};

    function compare(obj1, obj2, obj_) {
        for (let k in obj1) {
            var type = typeof obj1[k];
            if (type === 'object') {
                obj_[k] = {};
                if (!obj2[k]){
                    obj_[k] = false;
                }else if ((Object.entries(obj1[k]).length === 0 && obj1[k].constructor === Object) && (Object.entries(obj2[k]).length === 0 && obj2[k].constructor === Object)) {
                    obj_[k] = true;
                } else {
                    compare(obj1[k], obj2[k], obj_[k]);
                }
            } else {
                obj_[k] = (obj1[k] === obj2[k]);
            }

        }
    }

    if (Object.keys(obj1).length < Object.keys(obj2).length) { //check if both objects vary in length.
        var tmp = obj1;
        obj1 = obj2;
        obj2 = tmp;
    }

    compare(obj1, obj2, result);

    console.log(result);