Find intersecting point of three circles programmatically [closed]

Answer 1

You can use the following condition:

(x - x0) ^ 2 + (y - y0) ^ 2 <= R ^ 2

where x and y - coordinates of your point , x0 and y0 - coordinates of the center of the circle , R - radius of the circle , ^ 2 - squaring . If the condition is satisfied, the point is inside (or on the circumference in the case of equality of the left and right parts). If not satisfied, the point is outside the circle .

/ / Point, which hit the circle is necessary to determine
PointF p = ...;

/ / Center of the circle
PointF center = new PointF (10, 10);

/ / The radius of the circle
float r = 5F;

/ / "Normalize" the situation relative to the center point of the circle
float dx = p.x - center.x;
float dy = p.y - center.y;

/ / Compare the distance from the point to the center of a circle to its radius
boolean result =  ((r * r) <= (dx * dx + dy * dy))) ? true : false;