I\'m not looking for solution, I\'m looking for a better solution or just a different way to do this by using some other kind of list comprehension or something else.
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The first solution is elegant, but you could also use a generator expression instead of a list comprehension:
((x, y) for x in range(width) for y in range(height))
This might be more efficient, depending on what you're doing with the data, because it generates the values on the fly and doesn't store them anywhere.
This also produces a generator; in either case, you have to use list
to convert the data to a list.
>>> list(itertools.product(range(5), range(5)))
[(0, 0), (0, 1), (0, 2), (0, 3), (0, 4), (1, 0), (1, 1), (1, 2),
(1, 3), (1, 4), (2, 0), (2, 1), (2, 2), (2, 3), (2, 4), (3, 0),
(3, 1), (3, 2), (3, 3), (3, 4), (4, 0), (4, 1), (4, 2), (4, 3), (4, 4)]
Note that if you're using Python 2, you should probably use xrange
, but in Python 3, range
is fine.