Checking if bit is not set

Question

If I use this: if(value & 4) to check if the bit is set, then how do I check if the bit isn\'t set?

I tried with if(!value & 4) or

Answer 1

You could do it many ways, but the easiest (easiest as in requires the least amount of thought) would be just negate the entire expression you already have:

if (!(value & 4))