divide a range of values in bins of equal length: cut vs cut2

Question

I\'m using the cut function to split my data in equal bins, it does the job but I\'m not happy with the way it returns the values. What I need is the center of the bin not t

Answer 1

We can use smart_cut from package cutr:

devtools::install_github("moodymudskipper/cutr")
library(cutr)

Using @Joshua's sample data:

median by interval (same output as @Joshua except it's an ordered factor) :

smart_cut(x,3, "n_intervals", labels= ~ median(.))
# [1] 18 2  18 2  18 18 ...
# Levels: 2 < 11 < 18

center of each interval (same output as @Aaron except it's an ordered factor) :

smart_cut(x,3, "n_intervals", labels= ~ mean(.y))
# [1] 16.67 3.333 16.67 3.333 16.67 16.67 ...
# Levels: 3.333 < 10 < 16.67

mean of values by interval :

smart_cut(x,3, "n_intervals", labels= ~ mean(.))
# [1] 17.48 2.571 17.48 2.571 17.48 17.48 ...
# Levels: 2.571 < 11.06 < 17.48

labels can be a character vector just like in base::cut.default, but it can also be, as it is here, a function of 2 parameters, the first being the values contained in the bin, and the second the cut points of the bin.

more on cutr and smart_cut