How do I use a variable argument number in a bash script?

Question

#!/bin/bash
# Script to output the total size of requested filetype recursively

# Error out if no file types were provided
if [ $# -lt 1 ]
then 
  echo \"Syntax Err         


        

Answer 1

If all you're trying to do is loop over the arguments, try something like this:

for type in "$@"; do
    types="$types -o -name *.$type"
done

To get your code working though, try this:

#loop through additional filetypes and append
num=1
while [ $num -le $# ]
do
    (( num++ ))
    types=$types' -o -name *.'${!num}
done