Most efficient way to find the greatest of three ints

Question

Below is my pseudo code.

function highest(i, j, k)
{
  if(i > j && i > k)
  {
    return i;
  }
  else         


        

Answer 1

I think by "most efficient" you are talking about performance, trying not to waste computing resources. But you could be referring to writing fewer lines of code or maybe about the readability of your source code. I am providing an example below, and you can evaluate if you find something useful or if you prefer another version from the answers you received.

/* Java version, whose syntax is very similar to C++. Call this program "LargestOfThreeNumbers.java" */
class LargestOfThreeNumbers{
    public static void main(String args[]){
        int x, y, z, largest;
        x = 1;
        y = 2;
        z = 3;
        largest = x;
        if(y > x){
            largest = y;
            if(z > y){
                largest = z;
            }
        }else if(z > x){
            largest = z;
        }
        System.out.println("The largest number is: " + largest);
    }
}