I have some R code which performs some data extraction operation on all files in the current directory, using the following code:
files <- list.files(\".\
Because and forNelton took the response I was in the process of giving and Joran took the only other reasonable response I could think of and since I'm supposed to be writing a paper here's a ridiculous answer:
#I named your list LIST
LIST2 <- LIST[[1]]
lapply(2:length(LIST), function(i) {LIST2 <<- rbind(LIST2, LIST[[i]])})
data.frame(LIST2)