Run PHP function inside Bash (and keep the return in a bash variable)

Question

I am trying to run a PHP function inside Bash... but it is not working.

#! /bin/bash

/usr/bin/php << \'EOF\'

EOF
         


        

Answer 1

Use '-R' of php command line. It has a build-in variable that reads inputs.

VAR='/$#'
php_cwd=$(echo $VAR | php -R 'echo preg_quote($argn);')
echo $php_cwd