Not sure if I should\'ve posted this on math.stackexchange instead, but it includes more programming so I posted it here.
The question seems really simple, but I\'ve
I know this was 3 months ago but as an experiment because I am new to python I decided to try and combine some of the other people answers and I came up with a method you can pass the max number to and the divisors as a list and it returns the sum:
def sum_of_divisors(below, divisors):
return sum((n for n in xrange(below) if 0 in (n % d for d in divisors)))
max = 1000
nums = [3, 5]
print sum_of_divisors(max, nums)