Calling overloaded inherited methods using super class reference

Question

I do not understand this Java behavior. I have two classes:

class C1 {
    public void m1(double num) {
        System.out.println(\"Inside C1.m1(): \" + num         


        

Answer 1

Method signatures for both methods are different.

public void m1(double num) 
public void m1(int num)

So there is no overriding in this case. Now when you say

    C1 c = new C2();
    c.m1(10);

at compile time, it will se reference is of type C1 which has method public void m1(double num) which is compatible with 10 [int in expanded to double]. So int is promoted to double, and the corresponding method is called (which is also what you see in the bytecodes).