Is there an equivalent to the MATLAB
size()
command in Numpy?
In MATLAB,
>>> a = zeros(2,5) 0 0 0 0 0
This is called the "shape" in NumPy, and can be requested via the .shape attribute:
.shape
>>> a = zeros((2, 5)) >>> a.shape (2, 5)
If you prefer a function, you could also use numpy.shape(a).
numpy.shape(a)