Retry a Bash command with timeout

Question

How to retry a bash command until its status is ok or until a timeout is reached?

My best shot (I\'m looking for something simpler):

NEXT_WAIT_TIME=0         


        

Answer 1

retry fuction is from:

http://fahdshariff.blogspot.com/2014/02/retrying-commands-in-shell-scripts.html

#!/bin/bash

# Retries a command on failure.
# $1 - the max number of attempts
# $2... - the command to run
retry() {
    local -r -i max_attempts="$1"; shift
    local -r cmd="$@"
    local -i attempt_num=1

    until $cmd
    do
        if (( attempt_num == max_attempts ))
        then
            echo "Attempt $attempt_num failed and there are no more attempts left!"
            return 1
        else
            echo "Attempt $attempt_num failed! Trying again in $attempt_num seconds..."
            sleep $(( attempt_num++ ))
        fi
    done
}

# example usage:
retry 5 ls -ltr foo

if you want to retry an function in your script, you should do like this:

# example usage:
foo()
{
   #whatever you want do.
}

declare -fxr foo
retry 3 timeout 60 bash -ce 'foo'