Remove last argument from argument list of shell script (bash)

Question

This question concerns a bash script that is run in automator osx. I am using automator actions to get and filter a bunch of file references from the finder. Then I append t

Answer 1

You can also get all but the last argument with

"${@:0:$#}"

which, honestly, is a little sketchy, since it seems to be (ab)using the fact that arguments are numbered starting with 1, not 0.

Update: This only works due to a bug (fixed in 4.1.2 at the latest) in handling $@. It works in version 3.2.