numpy uint8 pixel wrapping solution

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离开以前
离开以前 2020-12-23 20:45

For an image processing class, I am doing point operations on monochrome images. Pixels are uint8 [0,255].

numpy uint8 will wrap. For example, 235+30 = 9. I need th

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  •  礼貌的吻别
    2020-12-23 21:26

    You can use OpenCV add or subtract functions (additional explanation here).

    >>> import numpy as np
    >>> import cv2
    >>> arr = np.array([100, 250, 255], dtype=np.uint8)
    >>> arr
    Out[1]: array([100, 250, 255], dtype=uint8)
    >>> cv2.add(arr, 10, arr)  # Inplace
    Out[2]: array([110, 255, 255], dtype=uint8)  # Saturated!
    >>> cv2.subtract(arr, 150, arr)
    Out[3]: array([  0, 105, 105], dtype=uint8)  # Truncated!
    

    Unfortunately it's impossible to use indexes for output array, so inplace calculations for each image channel may be performed in this, less efficient, way:

    arr[..., channel] = cv2.add(arr[..., channel], 40)
    

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