Defining an object without calling its constructor in C++

Question

In C++, I want to define an object as a member of a class like this:

Object myObject;

However doing this will try to call it\'s parameterle

Answer 1

A trick that involves anonymous union and placement new

this is similar to jenkas' answer but more direct

class Program
{
public:
   union{
   Object myObject;
   }; //being a union member in this case prevents the compiler from attempting to call the (undefined) default constructor
   
   Program()
   {
      ...

      //Now call the constructor
      new (&myObject) Object(...);
   }
   ~Program()
   {
      myobject.~Object(); //also make sure you explicitly call the object's destructor
   }

}

however the catch is that now you must explicitly define all the special member functions as the compiler will delete them by default.