I recently came across an interview question asked by Amazon and I am not able to find an optimized algorithm to solve this question:
You are given an input array wh
Here is one more solution written on Scala
def find(a: Array[Int]): Int = {
var count, left, right = 0
while (left < a.length - 1) {
right = a.length - 1
for (j <- a.length - 1 until left by -1) {
if (a(j) > a(right)) right = j
}
if (right - left > 1) {
for (k <- left + 1 until right) count += math.min(a(left), a(right)) - a(k)
left = right
} else left += 1
}
count
}