As I am just a learner, I am confused about the above question. How is a pointer to an array different from array of pointers? Please explain it to me, as I will have to exp
int a[10];
int (*ptr)[10];
Here ptr is an pointer to an array of 10 integers.
ptr = &a;
Now ptr
is pointing to array of 10 integers.
You need to parenthesis ptr
in order to access elements of array as (*ptr)[i]
cosider following example:
Sample code
#include
int main(){
int b[2] = {1, 2};
int i;
int (*c)[2] = &b;
for(i = 0; i < 2; i++){
printf(" b[%d] = (*c)[%d] = %d\n", i, i, (*c)[i]);
}
return 1;
}
Output:
b[0] = (*c)[0] = 1
b[1] = (*c)[1] = 2
int *ptr[10];
Here ptr[0],ptr[1]....ptr[9]
are pointers and can be used to store address of a variable.
Example:
main()
{
int a=10,b=20,c=30,d=40;
int *ptr[4];
ptr[0] = &a;
ptr[1] = &b;
ptr[2] = &c;
ptr[3] = &d;
printf("a = %d, b = %d, c = %d, d = %d\n",*ptr[0],*ptr[1],*ptr[2],*ptr[3]);
}
Output: a = 10, b = 20, c = 30, d = 40