How do I extract a file name into 2 parts, making one into directory and the other one inside of it?

Question

I\'m trying to sort all mp3 files by artist and name. At the moment, they\'re in 1 giant file name. E.g Artist - Song name.mp3 I want to convert this to Artist/Song name.mp

Answer 1

you can try this.

#!/usr/local/bin/bash
for f in *.mp3
do
artist=`echo $f | awk '{print $1}' FS=-`
song=`echo $f | awk '{print $2}' FS=-`
mkdir -p $artist
mv $artist-$song $song
mv $song ./$artist
done

here I am using two variable artist and song. as your test file name is "hi\ -\ hey" so I change the awk delimiter to "-" to store variable according to it.

we don't need to use awk..by using bash parameter expansion.... it is working.

#!/usr/local/bin/bash
for f in *.mp3
do
artist=`echo ${f%-*}`
song=`echo ${f#*-}`
mkdir -p $artist
mv $artist-$song $song
mv $song ./$artist
done