Take the intersection of an arbitrary number of lists in python

Question

Suppose I have a list of lists of elements which are all the same (i\'ll use ints in this example)

[range(100)[::4], range(100)[::3], range(100)         


        

Answer 1

Here's a one-liner using the good old all() built-in function:

list(num for num in data[0] 
     if all(num in range_ for range_ in data[1:]))

Interestingly, this is (I think) more readable and faster than using set for larger data sets.