Variable number of predictable for loops in Python

后端 未结 2 1829

I am trying to come up with a way to generate all possible unique strings from an alphabet of 20 characters where the order within the string doesn\'t matter, and the length

2条回答
  •  时光说笑
    2020-12-21 01:16

    1. the code for itertools.product does exactly what you want and is much more efficient that nested loops

    2. i suspect that what you really want is itertools.combinations_with_replacement

提交回复
热议问题