incrementing an array of pointers in C

Question

this is probably an essentially trivial thing, but it somewhat escapes me, thus far..

char * a3[2];
a3[0] = \"abc\";
a3[1] = \"def\";
char ** p;


Answer 1

a3 is a name of an array. This about it as a constant pointer.

You cannot change it. You could use a3 + 1 instead of ++a3.

Another problem is with the use of "%s" for the *(++a3) argument. Since a3 is an array of char, *a3 is a character and the appropriate format specifier should be %c.