How to display a byte array as hex values

Question

>>> struct.pack(\'2I\',12, 30)
b\'\\x0c\\x00\\x00\\x00\\x1e\\x00\\x00\\x00\'    
>>> struct.pack(\'2I\',12, 31)
b\'\\x0c\\x00\\x00\\x00\\x1f\\x00\\         


        

Answer 1

Try binascii.hexlify:

>>> import binascii
>>> import struct
>>> binascii.hexlify(struct.pack('2I',12,30))
b'0c0000001e000000'
>>> binascii.hexlify(struct.pack('2I',12,31))
b'0c0000001f000000'
>>> binascii.hexlify(struct.pack('2I',12,32))
b'0c00000020000000'
>>> binascii.hexlify(struct.pack('2I',12,33))
b'0c00000021000000'

Or if you want spaces to make it more readable:

>>> ' '.join(format(n,'02X') for n in struct.pack('2I',12,33))
'0C 00 00 00 21 00 00 00'

Python 3.6+, using f-strings:

>>> ' '.join(f'{n:02X}' for n in struct.pack('2I',12,33))
'0C 00 00 00 21 00 00 00'