PHP mySQLi_fetch_all: iterate through each row

Question

I am retrieving the rows of my query as such:

$rows = mysqli_fetch_all($result, MYSQLI_ASSOC);

How can I do:

(PSEUDO CODE)
         


        

Answer 1

I have written a small code, hope it solves the query.

    //Query to be executed;
$qry="select * from `tableName`";
//Performs a query on the database;
//here conn is a link identifier returned by mysqli_connect or mysqli_init function;
$result=mysqli_query($conn,$qry);
//Gets the number of rows in a result;
$rowcount=mysqli_num_rows($result);
//Fetches all result rows as an associative array;
$row = mysqli_fetch_all($result,MYSQLI_ASSOC);
//Iterating each row;
for($i=0;$i<$rowcount;$i++)
{
    echo "
 ".$row[$i]['`column_name_1`']." ".$row[$i]['`column_name_2`']." ".$row[$i]['`column_name_3`'];
}

Example Database Table Mysql Table snapshot Code

//here conn is a link identifier returned by mysqli_connect or mysqli_init function;
$conn = mysqli_connect("localhost","root","","nsgdb") or die('Error connecting to MySQL server.');
//Query to be executed;
$qry="select * from users";
//Performs a query on the database;
$result=mysqli_query($conn,$qry);
//Gets the number of rows in a result;
$rowcount=mysqli_num_rows($result);
//Fetches all result rows as an associative array;
$row = mysqli_fetch_all($result,MYSQLI_ASSOC);
//Iterating each row;
for($i=0;$i<$rowcount;$i++)
{
   echo "
 ".$row[$i]['id']." ".$row[$i]['user']." ".$row[$i]['pass'];
}

Output of the code