i am wondering :char *cs = .....;what will happen to strlen() and printf(\"%s\",cs) if cs point to memory block which is huge but with no \'\\0\' in it? i write these lines
If it's not null-terminated, then it's not a C string, and you can't use functions like strlen
- they will march off the end of the array, causing undefined behaviour. You'll need to keep track of the length some other way.
You can still print a non-terminated character array with printf
, as long as you give the length:
printf("str is %.3s",s2);
printf("str is %.*s",s2_length,s2);
or, if you have access to the array itself, not a pointer:
printf("str is %.*s", (int)(sizeof s2), s2);
You've also tagged the question C++: in that language, you usually want to avoid all this error-prone malarkey and use std::string
instead.