Copy constructor curly braces initialization

Question

\"we can initializate objects of a class for which we have not define any constructor using:

• memberwise initialization.
• copy

Answer 1

I think the behaviour conforms with 8.5.4 (List initialization), sentence 3:

List-initialization of an object or reference of type T is defined as follows:

— If T is an aggregate, aggregate initialization is performed (8.5.1).

[...]

— Otherwise, if the initializer list has a single element of type E [...] the object or reference is initialized from that element;

You were expecting the second item in my abbreviated quote to apply, but the first item takes precedence: Since Data is indeed an aggregate, the one-element-list clause is never considered.

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Your quote from the book appears to be a known error. The language is allegedly going to be fixed to match the book in C++14.