python -> combinations of numbers and letters

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醉话见心 2020-12-18 17:36
#!/usr/bin/python
import random
lower_a = [\'a\', \'b\', \'c\', \'d\', \'e\', \'f\', \'g\', \'h\', \'i\', \'j\', \'k\', \'l\', \'m\', \'n\', \'o\', \'p\', \'q\', \'r         


        
4条回答
  •  隐瞒了意图╮
    2020-12-18 18:01

    It's best not to recreate functionality that is already in the standard library.

    Take a look at the standard library module itertools. Particularly the combinations(), permutations(), and product() functions.

    import itertools
    
    lower_a = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
    upper_a = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
    num = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
    
    all = lower_a + upper_a + num
    
    for r in range(1, 3):
        for s in itertools.product(all, repeat=r):
             print ''.join(s)
    

    If your version of Python is old you may not have access to these functions. However if you take a look in the documentation for Python 2.6, you can see how all of these functions can be implemented in Python. For instance, the implementation of itertools.product is given as:

    def product(*args, **kwds):
        # product('ABCD', 'xy') --> Ax Ay Bx By Cx Cy Dx Dy
        # product(range(2), repeat=3) --> 000 001 010 011 100 101 110 111
        pools = map(tuple, args) * kwds.get('repeat', 1)
        result = [[]]
        for pool in pools:
            result = [x+[y] for x in result for y in pool]
        for prod in result:
            yield tuple(prod)
    

    You could also try a recursive solution instead:

    lower_a = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
    upper_a = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
    num = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
    
    all = lower_a + upper_a + num
    
    def recursive_product(myList, length, myString = ""):
        if length == 0:
            print myString
            return
        for c in myList:
            recursive_product(myList, length-1, myString + c)
        
    for r in range(1, 3):
        recursive_product(all, r)
    

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