PyQt run time issue

Question

I want my code to run by showing the qtwidget and then running the forloop, but it runs the forloop then shows my widget to me. Why is this?

class tes(QWid         


        

Answer 1

The widget is only shown once the application is running, not when its initialised. What exactly are you trying to do in the loop? It might be better to connect it to a signal or handle it in an event, but it all depends what you're trying to acheive.