How to convert javascript regex to safe java regex?

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广开言路
广开言路 2020-12-17 20:43
strOutput.replace(\"/{{[^]*?}}/g\",\"\");

Is there a way to convert JavaScript regexes to Java-safe regexes?

The above statement gives me t

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  •  时光说笑
    2020-12-17 21:10

    Get rid of the forward slashes. You don't need those in Java. Also, Java's flavor of regex doesn't recognize switches like /g and /i; those are controlled by constants in java.util.regex.Pattern.

    The only Javascript regex switches that make sense in the Java world are /i and /m. These map to Pattern.CASE_INSENSITIVE and Pattern.MULTILINE (you can use these switches when creating a regex from the Pattern class, or you can use them inline -- I'll show this later).

    The /g doesn't map to anything, but you can control replace behavior by using String.replaceAll versus String.replaceFirst.

    To get your code to work, you'd have to do something like this:

    strOutput.replaceAll("{{[^]*?}}", "");
    

    If you wanted to use switches, you need to do add something like (?i) to the beginning of the regex.

    You can't use String.replace because it takes in a CharSequence for the first argument and not a regex.

    Also keep in mind that the "quick regex" methods offered by the String class may not work like you expect it to. This is because when you specify a pattern (let's say abc) as a regex for matches for example, the actual pattern seen by Java is ^abc$. So abc will match, but abcd will not.

    There is more information here.

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