I know how to put an array in order, but in this case I just want to see if it is in order. An array of strings would be the easiest, I imagine, and answer
It looks like a generic abstraction, let's open Enumerable
:
module Enumerable
def sorted?
each_cons(2).all? { |a, b| (a <=> b) <= 0 }
end
end
[["a", 3], ["b", 53],["c", 2]].sorted? #=> true
Notice that we have to write (a <=> b) <= 0
instead of a <= b
because there are classes that support <=>
but not the comparator operators (i.e. Array), since they do not include the module Comparable.
You also said you'd like to have the ability "to check for order based on some arbitrary parameter":
module Enumerable
def sorted_by?
each_cons(2).all? { |a, b| ((yield a) <=> (yield b)) <= 0 }
end
end
[["a", 3], ["b", 1], ["c", 2]].sorted_by? { |k, v| v } #=> false
Using lazy enumerables (Ruby >= 2.1), we can reuse Enumerable#sorted?
:
module Enumerable
def sorted_by?(&block)
lazy.map(&block).sorted?
end
end