numpy random shuffle by row independently

Question

I have the following array:

 a= array([[  1,  2, 3],
           [  1,  2, 3],
           [  1,  2, 3])

I understand that np.random,sh

Answer 1

Good answer above. But I will throw in a quick and dirty way:

a = np.array([[1,2,3], [1,2,3], [1,2,3]])
ignore_list_outpput = [np.random.shuffle(x) for x in a]
Then, a can be something like this
array([[2, 1, 3],
       [4, 6, 5],
       [9, 7, 8]])

Not very elegant but you can get this job done with just one short line.