I have to check, if given number is divisible by 7, which is usualy done just by doing something like n % 7 == 0, but the problem is, that given number can have
n % 7 == 0
At first Take That Big Number in string And then sum every digit of string. at last check if(sum%7==0)
Code:
#include using namespace std; int main() { long long int n,i,j,sum,k; sum=0; string s; cin>>s; for(i=0;i