object name same a function name?

Question

If We have

var randomname = {};
randomname.attribute = \'something\';

function randomname(){
  alert(randomname.attribute);
}
randomname();

Answer 1

Your function randomname() is redefining the randomname identifier, thus losing your reference to the object you constructed earlier. It may look more clear like this:

var randomname = {};
randomname.attribute = 'something';

var randomname = function () {
  alert(randomname.attribute);
};

randomname();

It is like doing:

var a = 5;
var a = [20, 30];

console.log(a);  // returns [20, 30]