How to deserialize a float value with a localized decimal separator with Jackson

Question

The input stream I am parsing with Jackson contains latitude and longitude values such as here:

{
    \"name\": \"pr         


        

Answer 1

I came up with the following solution:

public class FlexibleFloatDeserializer extends JsonDeserializer {

    @Override
    public Float deserialize(JsonParser parser, DeserializationContext context)
            throws IOException {
        String floatString = parser.getText();
        if (floatString.contains(",")) {
            floatString = floatString.replace(",", ".");
        }
        return Float.valueOf(floatString);
    }

}

...

public class Product {

    @JsonProperty("name")
    public String name;
    @JsonDeserialize(using = FlexibleFloatDeserializer.class)
    @JsonProperty("latitude")
    public float latitude;
    @JsonDeserialize(using = FlexibleFloatDeserializer.class)
    @JsonProperty("longitude")
    public float longitude;

}

Still I wonder why I it does not work when I specify the return value class as as = Float.class as can be found in the documentation of JsonDeserialize. It reads as if I am supposed to use one or the other but not both. Whatsoever, the docs also claim that as = will be ignored when using = is defined:

if using() is also used it has precedence (since it directly specified deserializer, whereas this would only be used to locate the deserializer) and value of this annotation property is ignored.