Why do unsigned int x = -1 and int y = ~0 have the same binary representation?

Question

In the following code segment what will be:

• the result of function
• value of x
• value of y

    {
         unsigned int x=-1;         


        

Answer 1

If you run this program, you will see that the answer a is wrong and c is the correct answer:

#include 
#include 

int main() {
    unsigned int x=-1;
    int y;
    y = ~0;
    if(x == y)
        printf("same\n");
        if(x==INT_MAX) printf("INT_MAX\n");
        if(x==UINT_MAX) printf("UINT_MAX\n");
    else
        printf("not same");
    return 0;
}