I\'ve inherited the following DB design. Tables are:
customers
---------
customerid
customernumber
invoices
--------
invoiceid
amount
invoicepayments
Thank you very much for the replies!
Saggi Malachi, that query unfortunately sums the invoice amount in cases where there is more than one payment. Say there are two payments to a $39 invoice of $18 and $12. So rather than ending up with a result that looks like:
1 39.00 9.00
You'll end up with:
1 78.00 48.00
Charles Bretana, in the course of trimming my query down to the simplest possible query I (stupidly) omitted an additional table, customerinvoices, which provides a link between customers and invoices. This can be used to see invoices for which payments haven't made.
After much struggling, I think that the following query returns what I need it to:
SELECT DISTINCT i.invoiceid, i.amount, ISNULL(i.amount - p.amount, i.amount) AS amountdue
FROM invoices i
LEFT JOIN invoicepayments ip ON i.invoiceid = ip.invoiceid
LEFT JOIN customerinvoices ci ON i.invoiceid = ci.invoiceid
LEFT JOIN (
SELECT invoiceid, SUM(p.amount) amount
FROM invoicepayments ip
LEFT JOIN payments p ON ip.paymentid = p.paymentid
GROUP BY ip.invoiceid
) p
ON p.invoiceid = ip.invoiceid
LEFT JOIN payments p2 ON ip.paymentid = p2.paymentid
LEFT JOIN customers c ON ci.customerid = c.customerid
WHERE c.customernumber='100'
Would you guys concur?