Concatenate two numpy arrays in the 4th dimension

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一生所求
一生所求 2020-12-14 06:59

I have two numpy arrays with three dimensions (3 x 4 x 5) and I want to concatenate them so the result has four dimensions (3 x 4 x 5 x 2). In Matlab, this can be done with

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  •  有刺的猬
    2020-12-14 07:42

    The accepted answer above is great. But I'll add the following because I'm a math dork and it's a nice use of the fact that a.shape is a.T.shape[::-1]...i.e. taking a transpose reverses the order of the indices of a numpy array. So if you have your building blocks in an array called blocks, then the solution above is:

    new = np.concatenate([block[..., np.newaxis] for block in blocks],
                         axis=len(blocks[0].shape))
    

    but you could also do

    new2 = np.array([block.T for block in blocks]).T
    

    which I think reads more cleanly. It's worth noting that the already-accepted answer runs more quickly:

    %%timeit
    new = np.concatenate([block[..., np.newaxis] for block in blocks],
                         axis=len(blocks[0].shape))
    1000 loops, best of 3: 321 µs per loop
    

    while

    %%timeit
    new2 = np.array([block.T for block in blocks]).T
    1000 loops, best of 3: 407 µs per loop
    

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