.pyw and pythonw does not run under Windows 7

Question

Running a simple .py or .pyw python file causes python.exe to show up under Task Manager.

python myApp.py
python myApp.pyw

How

Answer 1

tl;dr

• To troubleshoot, use output redirection on invocation:

  pythonw myApp.py 1>stdout.txt 2>stderr.txt
  

This will capture stdout output, such as from print(), in file stdout.txt, and stderr output (such as from unhandled exceptions), in file stderr.txt; from PowerShell, use
cmd /c pythonw myApp.py 1>stdout.txt 2>stderr.txt).
Note that the very act of redirecting stdout may actually make your script work again, if the only reason for its failure with pythonw was the use of print (in Python 2.x - see below).
Caveat: This output redirection technique seemingly does not work when invoking *.pyw scripts directly (as opposed to by passing the script file path to pythonw.exe). ^{Do let me know if you know why and/or if it does work for you.}

• To fix your script:

Place the following at the top of any Python 2.x or 3.x script that you want to run with pythonw.exe:

import sys, os
if sys.executable.endswith("pythonw.exe"):
  sys.stdout = open(os.devnull, "w");
  sys.stderr = open(os.path.join(os.getenv("TEMP"), "stderr-"+os.path.basename(sys.argv[0])), "w")

This ensures the following when a script is run with pythonw.exe:

• print() calls and explicit calls to sys.stdout() are effectively ignored (are no-ops).
• Stderr output, including from an unhandled fatal exception, is sent to file %TEMP%\stderr-; %TEMP% is a standard Windows environment variable that points to the current user's folder for temporary files.

In other words: With the above code in place, check file %TEMP%\stderr- after your script has failed silently when invoked with pythonw.exe.

For an explanation, read on.

---

On Windows, pythonw.exe is for launching GUI/no-UI-at-all scripts, which means that the standard in- and output streams - sys.stdin, sys.stdout, sys.stderr are NOT available.

This has two nasty side effects:

• Using print() - which targets sys.stdout by default - causes an exception in Python 2.x.
  • This problem has been fixed in Python 3.x.
• Any unhandled exception - including one triggered by print() in 2.x - causes the script to abort silently.
  • Exception error messages go to sys.stderr by default, which is the very thing not available in this scenario.

The above code fixes these problems by:

• sending stdout output to the null device, effectively ignoring any attempt to output to sys.stdout - whether explicitly, or implicitly via print().

• sending all stderr output to a temporary file.

---

Differences between Python 2.x and Python 3.x:

When a script is run with pythonw.exe, sys.stdin, sys.stdout, and sys.stderr:

• in Python 2.x: have invalid file descriptors
  • The eventual result when trying to write to sys.stdout or sys.stderr is the following exception: IOError: [Errno 9] Bad file descriptor
  • Pitfall: Due to output buffering, this exception may not surface until you've output, say, 4K bytes; you can provoke it instantly by invoking pythonw.exe with -u (for unbuffered output).
  • print() blindly tries to sys.stdout (by default), so it provokes this exception sooner or later.
• in Python 3.x: are set to None
  • This is complemented with the 3.x print() function performing a no-op (doing nothing) when it finds that sys.stdout is None, so that print() statements can by default safely be used - they'll simply be ignored when run with pythonw.exe
  • However, it follows that trying to use sys.stdout.write() and sys.stderr.write() still results in an exception.

See here for more background.