How do I wrap a function in Javascript?

Question

I\'m writing a global error handling \"module\" for one of my applications.

One of the features I want to have is to be able to easily wrap a function with a t

Answer 1

Personally instead of polluting builtin objects I would go with a decorator technique:

var makeSafe = function(fn){
  return function(){
    try{
      return fn.apply(this, arguments);
    }catch(ex){
      ErrorHandler.Exception(ex);
    }
  };
};

You can use it like that:

function fnOriginal(a){
  console.log(1/a);
};

var fn2 = makeSafe(fnOriginal);
fn2(1);
fn2(0);
fn2("abracadabra!");

var obj = {
  method1: function(x){ /* do something */ },
  method2: function(x){ /* do something */ }
};

obj.safeMethod1 = makeSafe(obj.method1);
obj.method1(42);     // the original method
obj.safeMethod1(42); // the "safe" method

// let's override a method completely
obj.method2 = makeSafe(obj.method2);

But if you do feel like modifying prototypes, you can write it like that:

Function.prototype.TryCatchWrap = function(){
  var fn = this; // because we call it on the function itself
  // let's copy the rest from makeSafe()
  return function(){
    try{
      return fn.apply(this, arguments);
    }catch(ex){
      ErrorHandler.Exception(ex);
    }
  };
};

Obvious improvement will be to parameterize makeSafe() so you can specify what function to call in the catch block.