How to create a variadic generic lambda?

Question

Since C++14 we can use generic lambdas:

auto generic_lambda = [] (auto param) {};

This basically means that its call operator is templated

Answer 1

Consider this

#include 

    namespace {

        auto out_ = [] ( const auto & val_) 
        {
            std::cout << val_;
            return out_ ;
        };

        auto print = [](auto first_param, auto... params)
        {
            out_(first_param);

            // if there are  more params
            if constexpr (sizeof...(params) > 0) {
                // recurse
                print(params...);
            }
                return print;
        };
    }

int main()
{
    print("Hello ")("from ")("GCC ")(__VERSION__)(" !"); 
}

(wandbox here) This "print" lambda is:

• Variadic
• Recursive
• Generic
• Fast

And no templates in sight. (just underneath :) ) No C++ code that looks like radio noise. Simple, clean and most importantly:

• Easy to maintain

No wonder "it feels like a new language".