Is there a way to perform “if” in python's lambda

Question

In python 2.6, I want to do:

f = lambda x: if x==2 print x else raise Exception()
f(2) #should print \"2\"
f(3) #should throw an exception
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Answer 1

This snippet should help you:

x = lambda age: 'Older' if age > 30 else 'Younger'

print(x(40))