How to include variable in Regular expression pattern

Question

I am working on a vba macro which uses regular expression to search for a string pattern in another string.

Regex pattern includes a string (APR24 in code below) wh

Answer 1

You can specify whatever pattern you want in str2srch and then assign that to Regex.Pattern

For example

Sub Sample()
    Debug.Print Regexsrch("APR24ffffd", "APR24")  '<~~ Returns True
    Debug.Print Regexsrch("APR277ffffd", "APR24") '<~~ Returns False
End Sub

Public Function Regexsrch(ByVal str2bsrchd As String, ByVal str2srch As String) As Boolean
    Dim Regex As New VBScript_RegExp_55.RegExp
    Dim matches, s

    Regex.Pattern = str2srch
    Regex.IgnoreCase = True

    If Regex.Test(str2bsrchd) Then
         Regexsrch = True
    Else
        Regexsrch = False
    End If
End Function

FOLLOWUP

Even if it is dynamic you can always pass the pattern as

Debug.Print Regexsrch("APR24ffffd", "(\.|\s)" & VARIABLE & "(,|\s|\()").

This gives you the flexibility of using whatever pattern you want to pass to the function and you are not limited to one pattern...